Sapling 6


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Karina Rodriguez 2H
Posts: 50
Joined: Wed Sep 30, 2020 9:34 pm

Sapling 6

Postby Karina Rodriguez 2H » Sun Dec 06, 2020 7:56 pm

Give the oxidation state of the metal species in the complex [Co(NH3)4Cl2]Cl. Can someone explain how to do this?

Isaias Gomez D3A
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Joined: Wed Sep 30, 2020 9:37 pm
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Re: Sapling 6

Postby Isaias Gomez D3A » Sun Dec 06, 2020 8:00 pm

Well we know that Chlorine has a charge of -1 and there are 3 of them, giving us a charge of -3 from the Chlorines.
We also know that NH3 is neutral meaning it has a charge of 0.
If the whole compound has a neutral charge overall, that means Co must have a charge of +3 to cancel out the -3 from the the three chlorine atoms.

Sonel Raj 3I
Posts: 107
Joined: Wed Sep 30, 2020 9:48 pm

Re: Sapling 6

Postby Sonel Raj 3I » Sun Dec 06, 2020 8:05 pm

I am not 100% sure if this if always true, and it might vary, but so far in this section I have seen that the oxidation number is the same as the charge of the ion. The compound as a whole has a neutral charge, and the Cl3 has a 3- charge, and since we know the NH3 ligand is neutral (there's a chart in the book which might be helpful!), the charge of the Co would be 3+, and therefore the oxidation number would also be 3+.

Savannah Torella 1L
Posts: 52
Joined: Wed Sep 30, 2020 9:40 pm

Re: Sapling 6

Postby Savannah Torella 1L » Sun Dec 06, 2020 8:30 pm

To find the oxidation state of the metal, which is Co, you first have the recognize the charges of the other atoms. NH3 has no charge and each Cl has a -1 charge. Since the overall charge is zero, you can use the equation (0)= (Co charge)+(0)+(-2)+(-1). This gives the metal atom a +3 charge.


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