Midterm Question 8B

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Mike Matthews 1D
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Joined: Fri Sep 29, 2017 7:04 am

Midterm Question 8B

Postby Mike Matthews 1D » Sun Nov 26, 2017 8:07 pm

Midterm question 8b: "Draw the Lewis structure for the compound (HOCO)" When I drew the Lewis structure for this compound I gave one of the oxygens the extra, unpaired electron and it was wrong even though the formal charge of all of the atoms was zero. Could someone please explain to me why the unpaired electron must be placed on carbon and how they went about this problem. Thanks.

Eryn Wilkinson 3H
Posts: 20
Joined: Fri Sep 29, 2017 7:07 am

Re: Midterm Question 8B

Postby Eryn Wilkinson 3H » Sun Nov 26, 2017 8:14 pm

I drew it H-O-C=O with two lone pairs on each O and a single electron on the C. This has formal charges of 0 for all of the elements and gives each O a full octet, which makes sense because it is the more electronegative element so it should be pulling more electrons toward it. That's how I thought about it at least, hope it helps. :)

Rachel Wang
Posts: 49
Joined: Fri Sep 29, 2017 7:04 am

Re: Midterm Question 8B

Postby Rachel Wang » Fri Dec 08, 2017 10:06 pm

The lone electron is on Carbon because oxygen is more electroegative and therefore is more likely to attract enough e- to fill its octet.


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