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Midterm question 8b: "Draw the Lewis structure for the compound (HOCO)" When I drew the Lewis structure for this compound I gave one of the oxygens the extra, unpaired electron and it was wrong even though the formal charge of all of the atoms was zero. Could someone please explain to me why the unpaired electron must be placed on carbon and how they went about this problem. Thanks.
I drew it H-O-C=O with two lone pairs on each O and a single electron on the C. This has formal charges of 0 for all of the elements and gives each O a full octet, which makes sense because it is the more electronegative element so it should be pulling more electrons toward it. That's how I thought about it at least, hope it helps. :)
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