## d orbital period 3

melissa_dis4K
Posts: 106
Joined: Fri Sep 28, 2018 12:28 am

### d orbital period 3

I understand that Sulfur can have an expanded orbital, thus it has a d orbital. But if you do the electron configuration for Sulfur it is [Ne]3s^2 3p^4. I don't understand how it has a d orbital. Can someone please explain?

Brian Chhoy 4I
Posts: 66
Joined: Fri Sep 28, 2018 12:16 am

### Re: d orbital period 3

It has access to its d orbital because it is in the 3p block, which is close enough to the 3d sub shell to use when making bonds. However, in its ground state and when it is not making any bonds, its 3d sub shell is not in use.

Courtney Quan 1C
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am
Been upvoted: 2 times

### Re: d orbital period 3

As mentioned above, all elements in period 3 have access to their d-orbitals because their principal quantum number n=3. With n=3, the angular quantum number l can be 0, 1, and 2, which corresponds to s, p, and d-orbitals respectively. The d-orbital of sulfur simply isn't in use during its ground state, but can still be accessed to form an expanded octet.