### 2C.9

Posted:

**Thu Oct 31, 2019 5:43 pm**For 2C.9, when I did the correct Lewis Structure, I did not get a formal charge of 0 for Xe. What am I doing wrong?

Created by Dr. Laurence Lavelle

https://lavelle.chem.ucla.edu/forum/

https://lavelle.chem.ucla.edu/forum/viewtopic.php?f=34&t=49626

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Posted: **Thu Oct 31, 2019 5:43 pm**

For 2C.9, when I did the correct Lewis Structure, I did not get a formal charge of 0 for Xe. What am I doing wrong?

Posted: **Thu Oct 31, 2019 5:43 pm**

Sorry, I meant 2C.11 part c

Posted: **Thu Oct 31, 2019 8:32 pm**

Remember that formal charge equation is #valance electrons - ((bonding electrons/2) + electrons in lone pairs)

Posted: **Thu Oct 31, 2019 9:14 pm**

You can count the valences of electron of the Lewis structure and check that if it's equal to the number of valence of electrons you have calculated. Since there are 42 valences of electron in XeOF2, Xe has one lone pair.

Posted: **Fri Nov 01, 2019 3:11 pm**

If your lewis structure is correct, there will be a double bond between Xe and O, single bonds between each F and the Xe, and a lone pair on the central atom, Xe.

Now you take the equation for formal charge = V - (L + 1/2*B)

Since Xe is in the very last group it has a value of V = 8.

There are 2 lone pairs (L=2) and 12 electrons in bonded pairs (1/2*12=6)

8 - (2+6) = 0.

Now you take the equation for formal charge = V - (L + 1/2*B)

Since Xe is in the very last group it has a value of V = 8.

There are 2 lone pairs (L=2) and 12 electrons in bonded pairs (1/2*12=6)

8 - (2+6) = 0.