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I believe that any element from the third period and beyond (n=3) can make use of the expanded octet because of their access to the same principal energy level d-orbital, which allows for an expanded octet. Selenium, which is located in the period and is n=4, should have access to the empty 4d orbital, which is on the same principal energy level, and utilize it to form an expanded octet. This is the case for elements like Phosphorous (n=3) in PCl5, which utilizes the empty 3d orbitals to fulfill its expanded octet.
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