Textbook Question 2C.3

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Jaden Ji 2K
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Textbook Question 2C.3

Postby Jaden Ji 2K » Wed Nov 18, 2020 8:34 pm

How does iodine complete the octet rule with four single bonds to oxygens? Are the oxygens forming coordinate covalent bonds with the iodine?

Chem_Mod
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Re: Textbook Question 2C.3

Postby Chem_Mod » Thu Nov 19, 2020 8:40 am

Iodine completes the octet rule with 4 single bonds to oxygen because this equates to 8 shared electrons. Although, it still has a formal charge of +3 in that given Lewis Structure. Because oxygen and iodine have significantly different electronegativity values, a coordinate covalent bond is possible.

Mirren Solomon Discussion 2G
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Re: Textbook Question 2C.3

Postby Mirren Solomon Discussion 2G » Thu Nov 19, 2020 5:41 pm

The octet rule means that there are 8 total electrons. Since there are 4 single bonds and each bond has 2 electrons each, this is 4(2)=8. The octet is satisfied because each bond if worth 2 electrons not just one.

Kathy_Li_1H
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Re: Textbook Question 2C.3

Postby Kathy_Li_1H » Sun Nov 22, 2020 1:01 pm

Hi! Iodine can form its octet with 4 single bonds with oxygen because each bond involves 2 electrons being shared (yes all these bonds are covalent!); therefore, resulting in iodine's complete octet.

Jaden Ji 2K
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Re: Textbook Question 2C.3

Postby Jaden Ji 2K » Sun Nov 22, 2020 11:20 pm

I see! Thank you so much for the explanation.


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