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Today it was mentioned that boron forms the tetrafluoroborate anion (BF4-) with fluorine, provided that there is a coordinate bond. Yet when I search up the structure of BF4- online, none of the images contain an arrow between boron and fluorine. Would someone mind explaining this to me please? Thank you! :-)
Madelyn Romberg 3L wrote:Going off of this question, why does the boron trifluoride atom not form a coordinate covalent bond with the fluorine to get an octet opposed to adding an additional fluorine atom?
I think this is exactly what it does to form BF4-, where one of the F donates a pair of electrons to B. But as F only comes with 7 valence electrons, we would need an extra electron to be able to do that... hence the negative charge for the molecule.
Does that sound right?
Thank you guys! :-)
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