Can someone explain why carbonato (CO3^2-) can be either monodentate or bidentate?
The solution says it can bind a metal ion through either one or two of the oxygen ions.
How does this happen? And why is the third oxygen ion left out?
textbook 9C.5 b)
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Marcus Lagman 2A
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Re: textbook 9C.5 b)
Hello!
In order to determine how many sites of bonding the ligand, carbonate, can have, we must consider its shape through VSEPR model. Since there are three binding sites on the carbon atom, the formula would be AX3. From this, it is a trigonal planar.
Knowing its shape, we can see that only one or two oxygens can bind to a central metal as the other oxygen is too far to reach the central atom. In addition, one of the oxygen must have a pi bond due to one double bond so this restricts the flexibility of the molecule.
I hope this helps!
In order to determine how many sites of bonding the ligand, carbonate, can have, we must consider its shape through VSEPR model. Since there are three binding sites on the carbon atom, the formula would be AX3. From this, it is a trigonal planar.
Knowing its shape, we can see that only one or two oxygens can bind to a central metal as the other oxygen is too far to reach the central atom. In addition, one of the oxygen must have a pi bond due to one double bond so this restricts the flexibility of the molecule.
I hope this helps!
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