HW 3.59

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Ning_Yao_1B
Posts: 13
Joined: Wed Sep 21, 2016 2:59 pm

HW 3.59

Postby Ning_Yao_1B » Sat Oct 22, 2016 10:24 am

The question is to draw the Lewis structure of ClO.
I know it is a radical because the sum of valence electron is 13, an odd number.
However, if we are not given the electronegativity, how do we determine which atom should have the lone electron?

Shirley_Zhang 3O
Posts: 35
Joined: Wed Sep 21, 2016 2:56 pm

Re: HW 3.59

Postby Shirley_Zhang 3O » Sat Oct 22, 2016 1:14 pm

At this point, I would refer back to the octet rule.

Shirley_Zhang 3O
Posts: 35
Joined: Wed Sep 21, 2016 2:56 pm

Re: HW 3.59

Postby Shirley_Zhang 3O » Sat Oct 22, 2016 2:44 pm

After actually doing #59, and I used double bond; I think it would be better to put the extra electron on chlorine because chlorine can have expanded octet.
adding electron to oxygen would give you a final charge of -1 instead of zero


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