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churro 38

Posted: Sat Dec 08, 2018 12:50 am
by 405169322
between H2S and H2Se why does H2Se have a higher boiling point even though it has a weaker dipole-dipole?

Re: churro 38

Posted: Sat Dec 08, 2018 1:05 am
by Mahir_Hasan2C
Due to the fact it has a higher molar mass it is a bigger molecule, thus it requires more energy.

Re: churro 38

Posted: Sat Dec 08, 2018 2:39 am
by Richard Ku 4H
The mass of the molecule with Se is much greater, and hence will experience a greater level of London dispersion forces. Mass and London dispersion forces are proportional.

Re: churro 38

Posted: Sat Dec 08, 2018 7:51 am
by Claudia Luong 4K
Although H2S has stronger dipole-dipole forces, the LDFs in H2Se are stronger than that of H2S. These forces are strong enough to overcome even the dipole-dipole forces of H2S.