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Amide vs N-H

Posted: Wed Nov 27, 2019 9:13 am
by Jorja De Jesus 2C
Doesn't the double bond in amide already indicate that it has a stronger boiling point than N-H? (Amide has an N single bonded to a C, and then an H single bonded to the N and an O double bonded to the C) I thought that if the molecule has stronger bonds in it like a double or triple bond, it would have a higher boiling point than something that had only single bonds because it is harder to break a part? Why is this reasoning wrong?

Re: Amide vs N-H

Posted: Wed Nov 27, 2019 11:16 am
by Vicki Liu 2L
When thinking about boiling points, the focus should be on intermolecular forces and not actual bonds. Boiling means breaking apart the molecules from each other, as in lowering their concentration into a gaseous phase. What you're referring to is the breaking apart of the molecule itself, which involves bond dissociation energies and chemical reactions.

Re: Amide vs N-H

Posted: Wed Nov 27, 2019 2:13 pm
by Laura WM 3I
When determining boiling points, one needs to consider IMFs, which are interactions that occur between different molecules of a substance, not within the molecules. These interactions include hydrogen bonding, London dispersion forces, and dipole-dipole interactions. The boiling point depends on how strong a molecule's IMFs are and how many can form. The stronger the IMFs, the higher the boiling point.