London Dispersion Interaction

Moderators: Chem_Mod, Chem_Admin

Sheik Sahadat
Posts: 90
Joined: Fri Sep 29, 2023 12:07 pm

London Dispersion Interaction

Postby Sheik Sahadat » Thu Dec 07, 2023 2:43 pm

Hello,
Can someone please explain what E is proportional to (a1)(a2)/r^6 means? I think that E is the LDF interaction, showing that it's proportional to something. But I'm not too sure what all of the elements are representing or even what this means. I just remember it showing up on the midterm.
Thank you

Joseph Dekel 1F
Posts: 93
Joined: Fri Sep 29, 2023 10:54 am

Re: London Dispersion Interaction

Postby Joseph Dekel 1F » Thu Dec 07, 2023 2:59 pm

The formula E∝(a1∗a2)/r6 describes the London Dispersion Forces (LDF), a type of intermolecular force. Here, E is the energy of the LDF interaction, a1 and a2 represent the polarizabilities of two interacting particles (which measure how easily their electron clouds are distorted), and r is the distance between the particles. The equation shows that LDF energy is directly proportional to the product of the polarizabilities of the particles and inversely proportional to the sixth power of their separation distance.

Essentially what this means is that LDF is stronger between more polarizable molecules and decreases rapidly with increasing distance.

Hope this helps!


Return to “Bond Lengths & Energies”

Who is online

Users browsing this forum: No registered users and 1 guest