HW question 4.1

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Katarina Ho -1B
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Joined: Fri Apr 06, 2018 11:03 am

HW question 4.1

Postby Katarina Ho -1B » Mon May 28, 2018 11:15 pm

In this question why does part a have a lone pair, i thought that if the two bonds were so close together and angled down that neither of them could be a lone pair.

nikitasridhar_1b
Posts: 42
Joined: Fri Apr 06, 2018 11:05 am

Re: HW question 4.1

Postby nikitasridhar_1b » Mon May 28, 2018 11:23 pm

if there was no lone pair the bond angle would be 180 degrees. due to the repulsion of the lone pair, the bond angle is reduced from this number

Jennifer Ma 1G
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Joined: Fri Apr 06, 2018 11:03 am

Re: HW question 4.1

Postby Jennifer Ma 1G » Tue May 29, 2018 4:26 pm

Both the number of bonds and number of lone pairs take part in determining the shape of the molecule.

Namie Fotion-1E
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Joined: Fri Apr 06, 2018 11:02 am

Re: HW question 4.1

Postby Namie Fotion-1E » Tue May 29, 2018 4:41 pm

The bent shape is due to the fact that lone pairs exert a higher electron repulsion than shared electrons, so the lone pair is pushing the two side atoms down

Briana Lopez 4K
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Joined: Wed Nov 22, 2017 3:01 am

Re: HW question 4.1

Postby Briana Lopez 4K » Tue May 29, 2018 5:04 pm

The lone pairs are not shown, but if it were, then one would most likely be on top and the VSEPR would be AX2E1. The bond angle would be less than 120, but all of the angles would be about that much.

Myles Chang 1B
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Joined: Fri Apr 06, 2018 11:02 am

Re: HW question 4.1

Postby Myles Chang 1B » Sun Jun 03, 2018 9:27 pm

The lone pair is above the central atom, not represented by any of the three circles in the diagram. The question is referring to the fact that the lone pairs above the central atom repelling the other electrons to create a bent shape.


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