HW problem 6.99

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Rosamari Orduna 1D
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Joined: Fri Apr 06, 2018 11:04 am

HW problem 6.99

Postby Rosamari Orduna 1D » Tue May 29, 2018 6:44 pm

this question asks: Due to its strong hydrogen bonds, in the vapor, hydrogen fluoride is found as short chains and rings. Draw the Lewis structure of an (HF)3 chain and indicate the approximate bond angles.

I was able to draw the linear lewis structure chain, but
How are we to find the approximate angle for the bond between H-F-H?

Posts: 39
Joined: Fri Apr 06, 2018 11:05 am

Re: HW problem 6.99

Postby NatalieSDis1A » Tue May 29, 2018 8:28 pm

Hello I looked at this problem using Vsepr models. If we look at F - H ~ F (~ represents hydrogen bond) there are no lone pairs on H so we have AX2 and it is therefore linear and the bond angle is 180 degrees. Now looking at H - F ~ H we would have lone pairs. F already has 3 sets of lone pairs but one of those pairs is engaged in the hydrogen bond. If we count the hydrogen bond we get AX2E2 which is a bent molecule and the angle is therefore < 109.5 degrees.

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