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I am not completely positive but i believe bond order is the average bond length of the resonance hybrid. I am almost positive though that to calculate bond order you divide all the number of bonds between the central and outer atoms (sticks)and divide by the number of outer atoms that you used.
I actually think bond order is just based on the number of bonds between two atoms so F2 which has a single bond has a bond order of 1, O2 which has a double bond has a bond order of 2 and N2 which has a triple bond has a bond order of 3.
I am not confident you can truly define bond order with what you have learned. Bond order is the number of bonding electrons minus antibonding electrons, then that value divided by two. It has to do with molecular orbital theory and you have not covered this yet. For now, be familiar with single, double, triple bonds and how those impact bond lengths and strengths (more bonds, shorter distance and stronger).
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