## dissociation energy

bellaha4F
Posts: 104
Joined: Wed Sep 18, 2019 12:20 am

### dissociation energy

how do we calculate the dissociation energy? Is there a formula?

Daniel Honeychurch1C
Posts: 109
Joined: Thu Jul 11, 2019 12:15 am

### Re: dissociation energy

The dissociation energy of bonds will always be given because its based on experimental data.

Abhi Vempati 2H
Posts: 104
Joined: Fri Aug 09, 2019 12:17 am

### Re: dissociation energy

Like @Daniel Honeychurch 1B mentioned, for Chem 14A, we'll be given the experimental values of the dissociation energies. Professor Lavelle mentioned that we will be calculating dissociation energies in Chem 14B, though.

romina_4C
Posts: 100
Joined: Thu Jul 11, 2019 12:17 am

### Re: dissociation energy

I believe the only thing we need to know about bond dissociation energy for now is that stronger bonds have a larger dissociation energy (requires more energy to break them) and weaker bonds have a smaller dissociation energy (requires less energy to break them).

Chetas Holagunda 3H
Posts: 51
Joined: Thu Jul 11, 2019 12:17 am
Been upvoted: 1 time

### Re: dissociation energy

As the number of bonds increases too, like from a single, to double, to triple, the dissociation energy increases as the strength of the bond is more.

Megan Jung 3A
Posts: 50
Joined: Thu Jul 11, 2019 12:17 am

### Re: dissociation energy

Dissociation energies are measured values that have been experimentally calculated. Therefore, they will usually be given if you need to use the values and there isn't any formulas that we need to know for this class in terms of calculating the actual value.

Jordan Ziegler 2J
Posts: 59
Joined: Sat Aug 17, 2019 12:15 am

### Re: dissociation energy

I think our material only covers the definition and patterns surrounding dissociation energy. We will calculate the dissociation energy of bonds next quarter in Chem 14B. However, I remember in high school chemistry that bond dissociation energy is measured by the change in enthalpy ($\Delta H$
) as you break a bond.