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In the sapling homework, the solution has Si-S having a longer bond length than Si-O. I thought that since O has a larger atomic radius then the Si-O bond length would be longer. Why would Si-S have a longer bond length than Si-O?
The periodic trend for atomic radii is that it increases down a group! Since S is one period below O on the periodic table, it has a larger atomic radius and that's why the bond length would be larger.
Hi! S actually has a larger atomic radius as it has more electrons, which would make the bond length between Si-S longer than that of Si-O. Atomic radii increase down the period! And as S has a larger radius, it will have a longer bond length in comparison to O.
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