Fall 2015 Midterm Question 4

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Katelyn Li 2J
Posts: 27
Joined: Wed Sep 21, 2016 3:00 pm

Fall 2015 Midterm Question 4

Postby Katelyn Li 2J » Tue Nov 01, 2016 10:53 pm

For part 4Aii, it asks to draw and name the shape of XeF2 and give a bond angle. I drew the correct Lewis structure, but I'm confused as to why the shape is linear. I thought the side of Xe with two pairs of electrons would create more repulsive forces than the side with just one pair and result in a more bent structure. Can someone explain why this isn't the case?

Edgar Khachatryan 3G
Posts: 20
Joined: Fri Jul 15, 2016 3:00 am

Re: Fall 2015 Midterm Question 4

Postby Edgar Khachatryan 3G » Tue Nov 01, 2016 11:21 pm

Hi Katelyn!

The electron arrangement assumes the shape trigonal bipyramidal, however, when we take into account the 3 lone pairs, the molecular shape is in fact linear.

To see this more clearly, imagine a linear molecule(2 atoms on each end) and arrange the 3 lone pairs around the central atom. I will attach a link for you to get a better picture of this.

https://o.quizlet.com/tVEy0W8IRpeB3c7xZEfHgA.png


Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 2 guests