(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Kevin Liu 3G
Posts: 28
Joined: Fri Sep 29, 2017 7:07 am


Postby Kevin Liu 3G » Tue Nov 07, 2017 4:03 pm

For part A, I am getting 10 electrons from HCN where there is one bond between hydrogen and carbon and three bonds between carbon and nitrogen with one lone pair on nitrogen. Is that shape still linear?

nickjadidian 1A
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

Re: 4.3

Postby nickjadidian 1A » Tue Nov 07, 2017 4:21 pm

Yes, it will still be a linear shape. Even though the molecule "feels" skewed since on one side there are three covalent bonds, and on the opposite side there is only one covalent bond, this isn't the case. Remember that covalent bonds, whether single, double, or triple, have the same effect on the VSEPR shape. The only feature which would push the shape out of its linear state would be a lone pair present on the central atom. Lone pairs produce a strong repulsive force (even stronger than covalent bonds) and would push the H and C into an angular shape, for instance.

Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 1 guest