AXE

(Polar molecules, Non-polar molecules, etc.)

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Guadalupe T 1E
Posts: 58
Joined: Fri Sep 29, 2017 6:04 am

AXE

Postby Guadalupe T 1E » Mon Nov 13, 2017 7:40 pm

When doing the VSEPR formula I know how to find AX_n but how would you identify E or the subscript for it?

Cooper1C
Posts: 50
Joined: Fri Sep 29, 2017 6:07 am

Re: AXE

Postby Cooper1C » Mon Nov 13, 2017 7:47 pm

The subscript of E is the number of lone pairs around the central atom. You would have to draw the Lewis structure.

Angel Ni 2K
Posts: 50
Joined: Sat Jul 22, 2017 2:01 am

Re: AXE

Postby Angel Ni 2K » Mon Nov 13, 2017 7:49 pm

The notation is AX_E_, with the _ indicating the number of terminal atoms (X) or number of lone pairs (E). If there are no lone pairs, simply omit the E (you will end up with AX_). If there is one lone pair, omit the subscript (you will end up with AX_E). If there is more than one lone pair, you will end up with AX_E_.

Dang Lam
Posts: 55
Joined: Thu Jul 27, 2017 2:01 am

Re: AXE

Postby Dang Lam » Mon Nov 13, 2017 8:33 pm

A = central atom
X= an atom bonds to A
E= lone pair on A


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