14.15b  [ENDORSED]

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Isaac Eyler 1E
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Joined: Fri Sep 29, 2017 7:04 am

14.15b

Postby Isaac Eyler 1E » Wed Nov 15, 2017 12:14 am

The atom is TeCl4. The question asks to write the Lewis structure, VSEPR formula, shape, and predicted bond angles. I understand everything including the fact that it is See-Saw shaped. However, the solutions manual lists the bond angles as 90 degrees and 120 degrees. First, why are there two bond angles? Second, I understand where 90 degrees comes from, but which angle is 120 degrees and why is it 120 degrees?

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Re: 14.15b  [ENDORSED]

Postby Chem_Mod » Wed Nov 15, 2017 8:02 am

Bond angles between atoms on the equatorial positions are 120 degrees in a see-saw shape.


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