(Polar molecules, Non-polar molecules, etc.)
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In the answer key they explain that the bond between Be and the Carbons on either side of it are considered sp and linear. However, the CH3 on either side of the Be are considered tetrahedral because it connects to Be on one end and H on the other three. So you were right, the Be of the atom is not tetrahedral, but the C attached to it are.
The shape of (CH3)2Be is only tetrahedral about the carbon atoms as they both have 4 regions of electron density (3 hydrogens about them and are both bonded to Be). However, Be only has two regions of electron density, so the C-Be-C bond is linear with a bond angle of 180 degrees. Hope this helps!
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