3.3b bond angle
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3.3b bond angle
Postby cgarcia » Thu Oct 31, 2013 11:56 am
In 3.3, we have a ClO2+ ion. From the lewis structure, I was able to determine that there are four areas of electron density with two lone pairs giving it a VSEPR formula of AX2E2. I understand that the shape would be angular and it would be bent more than the shape of a molecule with VSEPR formula AX2E which has an angle less than 120. Using the fact that the ion was arranged in a tetrahedron which has bond angles of 109.5, I assumed that the bond angle in an AX2E2 would be less than 109.5. However, in the solutions manual, it only states that the bond angle would be less than 120. Could we say that the bond angles in an AX2E2 are less than 109.5? If we cannot, then why?
Re: 3.3b bond angle
Postby Twin 2 » Thu Oct 31, 2013 6:35 pm
I think that you may have drawn the lewis structure wrong.
It should be [O=Cl=O]+ With only one lone pair of electrons on Cl making it AX2E1. Making it bent.
Since it only has three areas of electron density the angle has to be <120o.
This compound is called Chloryl if you want to look it up.
It should be [O=Cl=O]+ With only one lone pair of electrons on Cl making it AX2E1. Making it bent.
Since it only has three areas of electron density the angle has to be <120o.
This compound is called Chloryl if you want to look it up.
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