4.3 Homework

(Polar molecules, Non-polar molecules, etc.)

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Bree Perkins 1E
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Joined: Fri Apr 06, 2018 11:04 am

4.3 Homework

Postby Bree Perkins 1E » Tue May 29, 2018 12:56 pm

Hi Everyone,

I am confused on problem 4.3. How can part a) HCN be linear. Wouldn't the lone pair on N cause it to not be linear?

Also, how do you know that is tetrahedral rather than trigonal planar?

KristinaNguyen_1A
Posts: 30
Joined: Fri Apr 06, 2018 11:04 am

Re: 4.3 Homework

Postby KristinaNguyen_1A » Tue May 29, 2018 1:11 pm

HCN is linear because C will be the central atom, single bonded to H and triple bonded to N, with N have a lone pair of electrons but, I think, because the lone pair is on the N and not the central atom it will not cause the bonds to be pushed and so it remains as a linear.

CH2N2 is a tetrahedral and not trigonal planar because there are no lone pairs on central atom C and C is bonded with 4 elements= Tetrahedral. It would only be a trigonal planar if its central atom is only bonded to 3 other atoms, AX3.

Harmonie Ahuna-1C
Posts: 30
Joined: Fri Apr 06, 2018 11:01 am

Re: 4.3 Homework

Postby Harmonie Ahuna-1C » Wed May 30, 2018 4:35 pm

HCN is linear because lone pairs only affect shape when they're on the central atom- so only if they were on carbon would we see a different shape. For CH2N2, C is the central atom paired with all 4 atoms, making it tetrahedral.

Celeste Martinez 1K
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Re: 4.3 Homework

Postby Celeste Martinez 1K » Thu May 31, 2018 9:06 pm

Since the lone pair is on nitrogen and not the central atom (carbon), then the shape is linear for HCN. CH2N2 is tetrahedral because carbon (center atom) is bonded with 4 atoms. If it was trigonal planar, carbon would've been bonded with three atoms.


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