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formal charge and VSEPR

Posted: Sat Jun 02, 2018 5:33 pm
by Jaquelinne Rodriguez-Lopez 1L
when figuring molecular shape, I've noticed that the textbook has Lewis structures that do not have the lowest formal charge. I know it does not matter as much because we can still figure out the shape. For the final do we draw the Lewis structure according to formal charge before figuring VSEPR shape?

Re: formal charge and VSEPR

Posted: Sat Jun 02, 2018 6:05 pm
by Jack Martinyan 1L
Yes, I believe the best habit to keep in mind is to draw the lewis structure with the lowest formal charge before applying VSEPR

Re: formal charge and VSEPR

Posted: Sat Jun 02, 2018 6:30 pm
by hannahtweedy
It's better to do it this way... but does anybody know if it's a necessity to be correct?

Re: formal charge and VSEPR

Posted: Sat Jun 02, 2018 8:20 pm
by Zuri Smith 1A
This is somewhat unrelated, but does VSEPR just refer to the notation? Like AXE4?

Re: formal charge and VSEPR

Posted: Sun Jun 03, 2018 12:49 pm
by Emma Leshan 1B
VSEPR refers to the notation and also the way of finding the molecular shape from the Lewis structure.

Re: formal charge and VSEPR

Posted: Thu Jun 07, 2018 2:52 am
by Jaquelinne Rodriguez-Lopez 1L
"This is somewhat unrelated, but does VSEPR just refer to the notation? Like AXE4?"
yes, AXE is the VSEPR formula

Re: formal charge and VSEPR

Posted: Fri Jun 08, 2018 11:44 am
by Jacy Black 1C
In determining formal charge, I know it is #valence electrons - #bonds and #lp. But, if there is one set of lone pairs (2 electrons, one Lone pair) would I just subtract 1 ? Or because there are two electrons, would I subtract two?

Re: formal charge and VSEPR

Posted: Fri Jun 08, 2018 12:43 pm
by Yadira Flores 1G
You would subtract one.

Re: formal charge and VSEPR

Posted: Fri Jun 08, 2018 9:28 pm
by MariaJohn1D
VESPR is used to predict molecular geometry using valence shell electrons