HW 4.19

(Polar molecules, Non-polar molecules, etc.)

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alexagreco1A
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Joined: Fri Apr 06, 2018 11:03 am

HW 4.19

Postby alexagreco1A » Sun Jun 03, 2018 5:30 pm

Predict the shapes and estimate the bond angles of (b) (CH3)2Be

Why is the shape tetrahedral if there are no lone pairs and only two bonds on the central atom?

Rosamari Orduna 1D
Posts: 31
Joined: Fri Apr 06, 2018 11:04 am

Re: HW 4.19

Postby Rosamari Orduna 1D » Sun Jun 03, 2018 6:00 pm

the overall compound is linear, but the 2 sub-compounds (CH3) are tetrahedral since the 3 H's and Be surround it

i hope this is somewhat clear :)
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Alexandra Wade 1L
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Re: HW 4.19

Postby Alexandra Wade 1L » Tue Jun 05, 2018 1:16 pm

With bigger molecules like this one, it will often be asked what the shape is surrounding an individual atom such as one of the Carbons in the atom. In this case you would say tetrahedral because there are 4 atoms around the central atom with no lone pairs.

John Miller-1I
Posts: 29
Joined: Fri Apr 06, 2018 11:04 am

Re: HW 4.19

Postby John Miller-1I » Wed Jun 13, 2018 3:16 pm

Since there are more than one "central" atoms in this molecule, the shape around one of these atoms can be determined the same way as if it were just a single compound with one central atom


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