4.19 d

(Polar molecules, Non-polar molecules, etc.)

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Husnia Safi - 1K
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Joined: Fri Sep 29, 2017 7:04 am

4.19 d

Postby Husnia Safi - 1K » Thu Jun 07, 2018 9:41 pm

So for 4.19 part d, it says that the shape is trigonal planar with bond angles of 95 degrees. I though that trigonal planar had bond angles of 120 degrees. I know this has something to do with the lone pairs but I don't really understand why. Thanks!

ElizabethP1L
Posts: 59
Joined: Wed Nov 15, 2017 3:01 am

Re: 4.19 d

Postby ElizabethP1L » Thu Jun 07, 2018 10:02 pm

Hi! I'm not sure where you got the 95 degrees from because I don't see that in the solutions manual. However, I can tell you that it will definitely be sightly less than 120 degrees because of the lone pair. Tin (Sn) has four valence electrons . Two of them form bonds with the 2 Cl atoms to complete their octets. Sn is left with a single lone pair. There are 3 regions of electron density. The lone pair takes up more space than the bonds and so it is pushing the other two Sn-Cl bonds closer together. The result is a smaller bond angle than the expected 120 degrees we see with trigonal planar. Hope this helped! :)


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