(CH3)2Be shape

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Andrea- 3J
Posts: 56
Joined: Tue Nov 14, 2017 3:00 am

(CH3)2Be shape

Postby Andrea- 3J » Thu Nov 08, 2018 6:32 pm

What is the difference between the solution manual saying (CH3)2Be is a tetrahedral while the molecule as a while is linear? Can someone explain this?

Posts: 19137
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 820 times

Re: (CH3)2Be shape

Postby Chem_Mod » Thu Nov 08, 2018 7:30 pm

The shape is tetrahedral with respect to the carbon atom because C has 4 regions of bonding density around it (3 H-C bonds, 1 Be-C bond). The shape as a whole (ie with respect to the central atom, Be) is linear because Be only has 2 regions of bonding density (2 Be-C bonds).

Riya Shah 4H
Posts: 65
Joined: Wed May 02, 2018 3:00 am

Re: (CH3)2Be shape

Postby Riya Shah 4H » Sat Nov 10, 2018 4:20 pm

So in such cases do we consider C as the central atom or Be? Do have to take into account and write both the shapes?

Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 5 guests