Question 4.5b Sixth Edition

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Posts: 24
Joined: Mon Jan 08, 2018 8:16 am

Question 4.5b Sixth Edition

Postby 904901860 » Tue Nov 13, 2018 6:39 pm

Does anyone know whether we use our answer for a in order to answer b? because if we just make the lewis structure for OClO, there's an odd number of electrons.

Posts: 82
Joined: Fri Sep 28, 2018 12:29 am

Re: Question 4.5b Sixth Edition

Postby Jeremy_Guiman2E » Tue Nov 13, 2018 7:53 pm

Yes, you'd be determining the bond angle for the ClO2+ ion.

The textbook calls it the OClO bond angle as it's just saying that the bond exists in this way (O - Cl - O), suggesting that Cl is the central atom with an O on both sides. Instead of saying angle ABC, it's saying Angle OClO.

Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 2 guests