Question 4.5b Sixth Edition
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Question 4.5b Sixth Edition
Does anyone know whether we use our answer for a in order to answer b? because if we just make the lewis structure for OClO, there's an odd number of electrons.
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Jeremy_Guiman2E
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Re: Question 4.5b Sixth Edition
Yes, you'd be determining the bond angle for the ClO2+ ion.
The textbook calls it the OClO bond angle as it's just saying that the bond exists in this way (O - Cl - O), suggesting that Cl is the central atom with an O on both sides. Instead of saying angle ABC, it's saying Angle OClO.
The textbook calls it the OClO bond angle as it's just saying that the bond exists in this way (O - Cl - O), suggesting that Cl is the central atom with an O on both sides. Instead of saying angle ABC, it's saying Angle OClO.
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