homework 2E #11 part b

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Leslie Cheng 4B
Posts: 35
Joined: Fri Sep 28, 2018 12:29 am

homework 2E #11 part b

Postby Leslie Cheng 4B » Wed Nov 14, 2018 10:03 pm

On the homework for Focus 2E #11 part b, the book asks you to predict the shape of iodine trichloride. Why is the molecule t-shaped instead of trigonal? I thought lone pair-lone pair repulsion is the strongest, and therefore the lone pairs would want to be the furthest away from each other and 180 degrees apart, but in a t-shape molecule, the lone pairs are next to each other.

Searra Harding 4I
Posts: 68
Joined: Fri Sep 28, 2018 12:29 am

Re: homework 2E #11 part b

Postby Searra Harding 4I » Wed Nov 14, 2018 10:33 pm

https://www.youtube.com/watch?v=wD004L8XlNg
This link shows a professor who explains the shape of Iodine Trichloride very well.
Attachments
Screen Shot 2018-11-14 at 10.21.19 PM.png

Kayla Vo 1B
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: homework 2E #11 part b

Postby Kayla Vo 1B » Wed Nov 14, 2018 11:04 pm

Another way to put it is that the molecule has 2 lone electron pairs and a Steric number of 5 (number of atoms bonded to a central atom of a molecule + the number of lone pairs attached to the central atom). Therefore, in terms of the VSEPR model it would be T-shaped.


Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: Eliana Carney 2F, Rich Luong 1B, Savana Maxfield 1G and 3 guests