Bond Angles in 7E 2E.13.b

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Jonathan Omens 1K
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Bond Angles in 7E 2E.13.b

Postby Jonathan Omens 1K » Sun Nov 18, 2018 10:28 pm

In this problem, the POCl3 molecule has a tetrahedral shape. In class we learned that tetrahedral molecules always have bond angles of 109.5o and this is the correct answer in the solutions manual. However, the bond angles are not exactly 109.5 because (I assume) of the double bond that the oxygen has with the phosphorous. Because of this, should we put that the bond angles are about 109.5 or just put exactly 109.5?

305008749
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Re: Bond Angles in 7E 2E.13.b

Postby 305008749 » Sun Nov 18, 2018 10:44 pm

The solutions manual says 109.5 so I'm assuming the double bond doesn't affect it?

Tessa Lawler 1A
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Re: Bond Angles in 7E 2E.13.b

Postby Tessa Lawler 1A » Sun Nov 18, 2018 11:45 pm

The solution manual says 109.5, so that’s probably your safest bet. I think that double bonds don’t affect bond angles as much as, say, lone pairs do.

Anand Narayan 1G
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Re: Bond Angles in 7E 2E.13.b

Postby Anand Narayan 1G » Mon Nov 19, 2018 11:40 am

Double bonds don't have nearly the same effect on bond angles that lone pairs do. Double bonds and single bonds both are the same electron density thus it doesn't affect the bond angle

Ibrahim Malik 1H
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Re: Bond Angles in 7E 2E.13.b

Postby Ibrahim Malik 1H » Mon Nov 19, 2018 11:57 am

Double bonds are almost negligible when finding bond angles, because we look at electron density in VSEPR, so double bonds and single bonds have the same value when calculating bond angles.


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