Molecular Shape

(Polar molecules, Non-polar molecules, etc.)

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Noh_Jasmine_1J
Posts: 71
Joined: Fri Sep 28, 2018 12:15 am

Molecular Shape

Postby Noh_Jasmine_1J » Wed Nov 21, 2018 7:42 am

for the names of the different shapes, is the only way to learn them is to memorize the names of the shapes that correspond to the AXE form?

MaanasO 1A
Posts: 72
Joined: Fri Sep 28, 2018 12:26 am

Re: Molecular Shape

Postby MaanasO 1A » Wed Nov 21, 2018 7:56 am

I think it would be better to understand how the shapes correspond to different AXE forms rather than simply memorize them. Some are nice, like trigonal planar. You know that if you have 3 regions of electron density around the central atom, then they all need to be equally spaced from each other (360/3 = 120). Some, like tetrahedral, may better be memorized.

AJ Manzano 3K
Posts: 16
Joined: Fri Sep 28, 2018 12:25 am

Re: Molecular Shape

Postby AJ Manzano 3K » Wed Nov 21, 2018 11:41 am

I find knowing how the actual shape looks like to be really helpful as it gives a clue onto the shape's name. For example a trigonal planar (AX3) looks like a triangle on a single plane, while a square pyramid (AX5E) looks like a pyramid with a square base if you connect the atoms (not the lone pairs) to create a 3D shape.

Sophia Fox 4B
Posts: 29
Joined: Fri Sep 28, 2018 12:27 am

Re: Molecular Shape

Postby Sophia Fox 4B » Wed Nov 21, 2018 11:56 am

Yeah. Could help to make a table w the following columns (this is what I’m doing): # lone pairs | # bonding pairs | AXE formula | name | hybridization | drawing / description. Hope that helps.

Ashita Tanwar 3H
Posts: 30
Joined: Fri Sep 28, 2018 12:23 am

Re: Molecular Shape

Postby Ashita Tanwar 3H » Sat Nov 24, 2018 12:37 am

Do the bond angles need to be memorized as well, or is there a formula that can determine what the angles are?

sallina_yehdego 2E
Posts: 75
Joined: Sun Apr 29, 2018 3:00 am

Re: Molecular Shape

Postby sallina_yehdego 2E » Sat Nov 24, 2018 9:32 am

I think you have to memorize those as well. Or you can look at the shape and determine it from there, but you would have to draw the shape correctly if you are looking doing it that way


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