HW 6TH EDITION 4.45

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Jeremiah Hutauruk
Posts: 67
Joined: Fri Sep 28, 2018 12:28 am

HW 6TH EDITION 4.45

Postby Jeremiah Hutauruk » Wed Nov 21, 2018 7:46 pm

4.45 Describe the structure of the formaldehyde molecule, CH2O, in terms of hybrid orbitals, bond angles, and - and -bonds. The C atom is the central atom to which the other three atoms are attached.

Jeffrey Xiao 4A
Posts: 35
Joined: Fri Sep 28, 2018 12:28 am
Been upvoted: 1 time

Re: HW 6TH EDITION 4.45

Postby Jeffrey Xiao 4A » Wed Nov 21, 2018 9:23 pm

Well, first you would draw the Lewis structure of CH2O then count number of electron densities around central atom which should be 3 (two C-H single bonds and one double bond between C and O). As a result, hybrid orbitals would be sp2 since there are three electron densities, and then you would figure out the shape which is trigonal planar so bond angles must be 120degrees and from the bonds, there must be 3 sigma bonds and 1 pi bond as there are two single bonds (=2 sigma bonds) and one double bond (1 pi +1 sigma bond).


Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 2 guests