2E.11 7th edition

(Polar molecules, Non-polar molecules, etc.)

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Hailey Boehm 2H
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2E.11 7th edition

Postby Hailey Boehm 2H » Fri Nov 23, 2018 10:23 pm

2E.11 asks you to "use lewis structures and the VSEPR model to give the VSEPR formula for each of the following species and predict its shape"
part d asks you to do this for Xenon Trioxide, XeO3.
Why is the correct molecular geometry trigonal pyramidal? What would this look like?

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Re: 2E.11 7th edition

Postby Chem_Mod » Fri Nov 23, 2018 10:32 pm

There are three oxygen atoms. Each oxygen atom is double bonded to the xenon. Because xenon has 8 valence electrons, one lone pair lies on the xenon central atom. Thus, there are four groups around, making it have a tetrahedral electron geometry. However, because of that one lone pair, it's molecular geometry is trigonal pyramidal.


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