Molecular Shape 4.45

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Semi Yoon
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Joined: Fri Sep 28, 2018 12:27 am

Molecular Shape 4.45

Postby Semi Yoon » Sat Nov 24, 2018 7:24 pm

How would you describe the structure of the formaldehyde molecule, CH2O, in terms of hybrid orbitals, bond angles, and pi- and sigma-bonds. The C atom is the central atom to which the other three atoms are attached.

Joon Chang 2F
Posts: 59
Joined: Fri Sep 28, 2018 12:25 am

Re: Molecular Shape 4.45

Postby Joon Chang 2F » Sat Nov 24, 2018 8:24 pm

Formaldehyde is trigonal planar so it has angles of 120 degrees. It has a hybridization of sp2 and has 3 sigma and 1 pi bonds.

Kevin Tang 4L
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Joined: Fri Sep 28, 2018 12:28 am

Re: Molecular Shape 4.45

Postby Kevin Tang 4L » Sun Nov 25, 2018 12:08 am

CH2O's central atom, Carbon, has two single bonds and one double bond, the first bond is sigma and one of the bonds in the double bond is a pi bond. So there are three sigma bonds and one pi bond. CH2O is sp2 hybridized and has a shape of trigonal planar. See 4.1, pg 109 in 6th Edition.

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Joined: Fri Sep 28, 2018 12:27 am

Re: Molecular Shape 4.45

Postby sonalivij » Sun Nov 25, 2018 12:15 am

Carbon has a single bond with both the hydrogen atoms and a double bond with the oxygen atom (which has two lone pairs on it but we don't need to know that, just to help you visualize the lewis structure).
CH2O would have three bonding domains, making its hybridization sp2
There are two single bonds that have one sigma bond each, and a double bond with one sigma bond and one pi bond
Lastly, the VSEPR formula would be AX3, meaning the shape is trigonal planar and the bond angles are all 120 degrees

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