VSEPR model

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Emily Orozco L4
Posts: 22
Joined: Fri Sep 28, 2018 12:29 am

VSEPR model

Postby Emily Orozco L4 » Sun Nov 25, 2018 11:30 pm

What does the "A", "X", and "E" tell us about how the model should look?

404536963
Posts: 29
Joined: Fri Feb 02, 2018 3:02 am

Re: VSEPR model

Postby 404536963 » Sun Nov 25, 2018 11:35 pm

The A tells us which is the central atom, the X tells us the ligands/bonds attached to the central atom, and E tells us the nonbonding electron pairs (and lowercase e shows nonbonding lone electrons). So, for example, AX2E could be SO2 because S is the central atom, it has two bonds with two Os, and has one lone pair.

305117729
Posts: 30
Joined: Fri Sep 28, 2018 12:16 am

Re: VSEPR model

Postby 305117729 » Sun Nov 25, 2018 11:37 pm

A is the central atom, X is the atom bond to A, and E is lone pair electrons on A. Knowing this, we are able to know the number of electron density around the central atom A. e.g. AX4 stands for 4 atoms bond to central atom, and there's no lone pairs, so there are 4 electron density around A, and therefore we know the molecular shape is tetrahedral, hybridization sp3.

Minsub Lee 3E
Posts: 32
Joined: Fri Sep 28, 2018 12:25 am

Re: VSEPR model

Postby Minsub Lee 3E » Sun Nov 25, 2018 11:37 pm

'A' refers to the central atom, 'X' refers to the bonded atom, and 'E' refers to lone pair. By knowing how much of each are there, you can determine how many atoms and lone pairs there are, and then determine the shape of the molecule.

megansardina2G
Posts: 61
Joined: Fri Sep 28, 2018 12:23 am
Been upvoted: 2 times

Re: VSEPR model

Postby megansardina2G » Sun Nov 25, 2018 11:39 pm

Hi! A refers to the central atom of the molecule, X refers to the atoms attached to the central atom in the molecule, and E refers to the lone pairs on the central atom. For example, XeF4 has four bonding pairs and two lone pairs, so it would be AX4E2. Hope this helps!


Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 1 guest