Homework question

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Posts: 132
Joined: Fri Sep 28, 2018 12:27 am

Homework question

Postby sarahtang4B » Mon Nov 26, 2018 9:33 pm

On homework 2.E.19 how do we draw the structure of (CH3)2Be?
Will we be required to know how to draw the lewis structure to determine shape and bond angles? or will test 3 have easier lewis structures than this to determine shapes.

Jake Gordon 1A
Posts: 61
Joined: Fri Sep 28, 2018 12:15 am

Re: Homework question

Postby Jake Gordon 1A » Mon Nov 26, 2018 10:57 pm

I believe Be is linear between the carbons and each carbon has 3 hydrogens in a tetrahedral arrangement. The formal charge should work out to be 0. Tetrahedral has a bond angle of 109.5 and linear is 180


Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 3 guests