4.15 6th Edition

(Polar molecules, Non-polar molecules, etc.)

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Dustin Shin 2I
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4.15 6th Edition

Postby Dustin Shin 2I » Wed Nov 28, 2018 4:25 am

Can someone explain part b of 4.15? My brain is slipping and I cannot figure it out for the life of me.

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Joined: Fri Sep 28, 2018 12:25 am

Re: 4.15 6th Edition

Postby Lynsea_Southwick_2K » Wed Nov 28, 2018 9:16 am

4.15 Write the Lewis structure and the VSEPR formula, list the shape, and predict the approximate bond angles
b) TeCL4
Te has 6 e-, Cl has 7e- times 4 = 28e-. 28+6= 34e-. Lewis structure must have 34e-.

Lewis Structure: Te is the central atom, there are 4 Cl's around the Te, they all connect with a single bond.
Each Cl has 3 lone pairs and the bond to Te.
Te has the four bonds to the Cl's and one lone pair.
VSEPR: A is central atom, X is how many bonds central atom has, E is how many lone pairs central atom has.
Te has 4 bonds and one lone pair so AX4E1
Shape: Looking at the lewis structure the shape is SEESAW
Angles:The SEESAW shape has 90 degree angles and one 120 degree angle.

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