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Lone pairs on octahedral electron density

Posted: Wed Nov 28, 2018 11:48 am
by Shivangi_2J
For all of the other VSEPR models, replacing an atom with a lone pair is done by taking away from the equatorial plane. But with the octahedral shape, an axial bond is replaced to form square pyramidal. Why is that so?

Re: Lone pairs on octahedral electron density

Posted: Wed Nov 28, 2018 11:57 am
by timschaeffer Dis 1J
due to the symmetry of the octahedral shape, it doesn't matter where the first atom is removed from (axial or equatorial) because it will always result in a square pyramidal shape
Octahedral-3D-balls.png
Octahedral-3D-balls.png (23.37 KiB) Viewed 88 times

Re: Lone pairs on octahedral electron density

Posted: Fri Dec 07, 2018 4:57 pm
by Cameron_Greenberg_3C
The axes are not relevant for an octahedral shaped molecule because the shape is the same no matter how the molecule is rotated. So any of the planes can have the four atoms with the two lone pairs above and below.

Re: Lone pairs on octahedral electron density

Posted: Fri Dec 07, 2018 8:22 pm
by Ivan Tadeja 4B
With every other VSEPR shape, 1 removed molecule removed will affect the configuration in different ways with respect to the one removed, thus resulting in different possible bond angles in some. With octahedral, no matter which one is removed, the result will always be the same.