AX2E2

[Phoebe Chen 4I]

Molecules with the VSEPR formula AX2E2 would have bond angles of 109.5 or less than 109.5?

[Megan Gianna Uy 3L]

Molecules with the molecular formula AX2E2 have four regions of electron density so its electron geometry would be tetrahedral. Its molecular geometry would be bent with a bond angle of <<109.5.

[Michael Nirula]

Yes, bent molecular geometry with bond angles less than 109.5

[Nicole Lee 4E]

Its bond angles are less than 109.5 because of the presence of lone pairs.

[Danny Zhang 4L]

The VESPR formula AX2E2 suggests that the shape of the molecule is bent/angular, which means that the bond angles are less than 109.5 degrees.

[Carlos De La Torre 2L]

a molecule with formula AX2E2 will have a bond angle >>109.5 as the lone pairs repulse the atoms more that atoms repulse atoms, however a molecule with formula AX4E2 will have bond angles at exactly 90 degrees as the lone pair-atom repulsion will cancel out.

[Elle_Mendelson_2K]

On the exam, will we need to write << or can we just write < ?

[g orloff 1J]

The bond angles will be less than 109.5 due to the lone pairs pushing harder than the bound atoms.

[Katie_Duong_1D]

AX2E2 would have a bond angle of less than 109.5 degrees. A molecule with this VSEPR formula has 4 regions of electron density: 2 shared and 2 lone pairs. The electron geometry is tetrahedral, but the molecular geometry is bent because the 2 lone pairs on the central atom would slightly bring the atoms closer to each other. This would mean that the bond angle is less than 109.5 degrees, instead of 109.5 degrees exactly.

[Karina Jiayu Xu 4E]

Because the lone pairs are more negative than an atom, it pushes harder on the two bonded atoms, thus making the angle between them less than 109.5.

[Avery Zuelch 1D]

what would make the bond angles equal to 109.5? or are they always less than it?

[Madison Gil 3D]

A molecule with a VSEPR formula of AX2E2 would have a bent or v-shaped structure of atoms. A molecule with 4 things coming off of it (tetrahedral) would have bond angles of 109.5, but since two of these are lone pairs of electrons, the electrons will push other atoms away from it, lowering the bond angle from 109.5 to <<109.5.

[Arshia Ramesh 1G]

the bond angle should be less than 109.5 because of the lone pair repulsion

[Stevin1H]

The VSEPR formula of AX2E2 suggests that the molecular shape will be bent, though it has 4 electron density regions. And for 4 electron density regions, it suggests the electron pair geometry would be tetrahedral, which has bond angles of 109.5. But for AX2E2, it has lone pairs so the bond angles will be slightly less than 109.5.

[Ricardo Martin 1J]

Yes this is a bent shape with bond angles less than 109.5