VSEPR in equal angles

(Polar molecules, Non-polar molecules, etc.)

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Ryan Troutman 4L
Posts: 68
Joined: Fri Sep 28, 2018 12:22 am

VSEPR in equal angles

Postby Ryan Troutman 4L » Thu Nov 29, 2018 6:06 pm

If you have atoms that are linear, trigonal planar, octahedral, tetrahedral (basically all the bond angles are the same), are they all non-polar molecules since they have equal angles? I was doing some practice problems and was confused by this concept.

Yiting_Gong_4L
Posts: 69
Joined: Fri Sep 28, 2018 12:25 am

Re: VSEPR in equal angles

Postby Yiting_Gong_4L » Thu Nov 29, 2018 6:07 pm

yes

timschaeffer Dis 1J
Posts: 38
Joined: Fri Sep 28, 2018 12:18 am

Re: VSEPR in equal angles

Postby timschaeffer Dis 1J » Thu Nov 29, 2018 7:09 pm

This is only 100% true when all of the atoms attached to the central atom are of the same element. If the atoms are all different from one another, then the different dipole moments will likely result in a net dipole moment that makes the molecule polar, even if the geometric shape is symmetrical.

Cameron_Greenberg_3C
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: VSEPR in equal angles

Postby Cameron_Greenberg_3C » Fri Dec 07, 2018 2:42 pm

If there are no lone pairs present, then the atoms will be symmetrically arranged around the center atom. If they are all the same element, then yes, the molecule will be non-polar. But if there is a large electronegativity difference, then the molecule could be polar.

Minsub Lee 3E
Posts: 32
Joined: Fri Sep 28, 2018 12:25 am

Re: VSEPR in equal angles

Postby Minsub Lee 3E » Fri Dec 07, 2018 2:50 pm

Yes, like what most people said, the molecule is nonpolar unless the bonded atoms are not uniform. An example of this is CH4 and CClH3. Although both molecules have a tetrahedral molecular shape, CClH3 is polar because the partial charge given by the electronegativity difference of the chlorine atom that is bonded.


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