Molecular shape

(Polar molecules, Non-polar molecules, etc.)

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melissa_dis4K
Posts: 106
Joined: Fri Sep 28, 2018 12:28 am

Molecular shape

Postby melissa_dis4K » Fri Dec 07, 2018 1:14 am

To find the molecular shape of [Pt(NH3)5Cl]Br3 do I have to find the coordination number? And if so, isn't it 7? And the answer for this is octahedral does this mean that anything above 6 is octahedral? Or am I doing this wrong? Thanks!

Mikka Hoffman 1C
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Joined: Fri Sep 28, 2018 12:23 am
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Re: Molecular shape

Postby Mikka Hoffman 1C » Fri Dec 07, 2018 11:08 am

I think the coordination number for this is actually 6 because the central platinum atom is bonded to 5 chlorines and 1 ammonia. This would explain why it's octahedral because octahedral is something with 6 regions of electron density.

Michael Novelo 4G
Posts: 64
Joined: Fri Sep 28, 2018 12:28 am

Re: Molecular shape

Postby Michael Novelo 4G » Fri Dec 07, 2018 11:48 am

I believe whatever is in the brackets is what ligands are attached to the metal atom in this case 5 ammonia (if the 5 is the subscript of ammonia) and 1 Chlorine for a total of 6 coordination. The Br3 is left out since it's not being coordinated with Pt

melissa_dis4K
Posts: 106
Joined: Fri Sep 28, 2018 12:28 am

Re: Molecular shape

Postby melissa_dis4K » Fri Dec 07, 2018 10:11 pm

Thank you! That makes sense, so to clarify the Pt is the central transition metal atom therefore I shouldn't have included it as a seventh ligand. I got confused because it was inside the brackets. May I ask what the Br3 is then?Is it just another molecule attaching to it not part of the coordination complex, correct?


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