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Molecular shape

Posted: Fri Dec 07, 2018 1:14 am
by melissa_dis4K
To find the molecular shape of [Pt(NH3)5Cl]Br3 do I have to find the coordination number? And if so, isn't it 7? And the answer for this is octahedral does this mean that anything above 6 is octahedral? Or am I doing this wrong? Thanks!

Re: Molecular shape

Posted: Fri Dec 07, 2018 11:08 am
by Mikka Hoffman 1C
I think the coordination number for this is actually 6 because the central platinum atom is bonded to 5 chlorines and 1 ammonia. This would explain why it's octahedral because octahedral is something with 6 regions of electron density.

Re: Molecular shape

Posted: Fri Dec 07, 2018 11:48 am
by Michael Novelo 4G
I believe whatever is in the brackets is what ligands are attached to the metal atom in this case 5 ammonia (if the 5 is the subscript of ammonia) and 1 Chlorine for a total of 6 coordination. The Br3 is left out since it's not being coordinated with Pt

Re: Molecular shape

Posted: Fri Dec 07, 2018 10:11 pm
by melissa_dis4K
Thank you! That makes sense, so to clarify the Pt is the central transition metal atom therefore I shouldn't have included it as a seventh ligand. I got confused because it was inside the brackets. May I ask what the Br3 is then?Is it just another molecule attaching to it not part of the coordination complex, correct?