Lewis Structure

(Polar molecules, Non-polar molecules, etc.)

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Lewis Structure

Postby 905174774 » Sun Oct 20, 2019 9:16 pm

For the lewis structure, do we add more elections when the problem adds a "-(x amount of e)" to the structure regardless of the amount of elections?

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Re: Lewis Structure

Postby Chem_Mod » Sun Oct 20, 2019 11:13 pm

I think this question may be more easily answered if you gave us the specific example you're referring to.
In general, you do not want to add more electrons than an element's orbitals can contain. For most elements, the maximum amount of valence electrons is 8, however there are notable exceptions where atoms may have expanded octets, such as Sulfur and Phosphorus.

Jacob Motawakel
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Re: Lewis Structure

Postby Jacob Motawakel » Sun Oct 20, 2019 11:19 pm

The negative implies that the structure has a negative charge and therefore more electrons. You would have to take this into account when making the Lewis structure by adding the additional electron to the total amount.

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Re: Lewis Structure

Postby BCaballero_4F » Wed Oct 30, 2019 6:13 pm

If the negative is referring to the charge then yes you would add an electron for every negative shown and subtract an electron for every positive shown when referring to charge.

Kaitlyn Jang 1F
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Re: Lewis Structure

Postby Kaitlyn Jang 1F » Sat Nov 02, 2019 9:52 am

If there is a negative charge, then you add however many more electrons are shown in the number of the charge. Conversely, if there is a positive charge then you subtract however many number of electrons that the charge shows.

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Re: Lewis Structure

Postby nickianel_4b » Sat Nov 02, 2019 3:54 pm

Also important to note is that when drawing the Lewis structure of ions, after you've finished, draw brackets around the whole thing and write the charge outside the brackets.

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