2E.11d)

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Hannah Lee 2F
Posts: 117
Joined: Thu Jul 11, 2019 12:15 am

2E.11d)

Postby Hannah Lee 2F » Thu Nov 14, 2019 9:56 am

Use Lewis structures and the VSEPR model to give the VSEPR formula for each of the following species and predict its shape: (d) xenon trioxide.

When drawing the Lewis structure for XeO3, does it have to be structured in a tetrahedral arrangement (other than the 1 lone pair)? I thought that the presence of the lone pair would reduce the bond angles between O-Xe-O, making it slightly less than the bond angle for a tetrahedral structure. However, the answer key visualizes the Lewis structure for the O=Xe=O angle as almost 90 degrees. Which way is the correct way to draw the Lewis structure, or does either way work?

Kayli Choy 2F
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am

Re: 2E.11d)

Postby Kayli Choy 2F » Thu Nov 14, 2019 10:10 am

Lewis structures are not representative of molecular shape, so even if the molecules are drawn with 90 degree angles, this does not mean that the bond angles are 90 degrees. Therefore, either way works for the Lewis structure.

Camellia Liu 1J
Posts: 51
Joined: Sat Aug 24, 2019 12:15 am

Re: 2E.11d)

Postby Camellia Liu 1J » Thu Nov 14, 2019 10:15 am

Lewis structures don't determine the shapes of the molecules, but it is the first step in helping to predict it as it helps to identify the bond pairs and the lone pairs. Then, you can apply VSEPR to determine molecular shape/geometry.


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