Bent shape and angles

[Luyan Zhang - 2D]

Both VSEPR shape with the formula AX2E and AX2E2 have bent shape. What are the differences in their bond angles?

[Jedrick Zablan 3L]

AX2E has a bond angle near 120 degrees while AX2E2 has a bond angle near 109.5 degrees.

[KDang_1D]

The VSPER theory only gives qualitative, not quantitative descriptions of the shape of molecules, so although we know how the atoms are arranged, we cannot predict exactly what their angles will be.

AX2E will be less than 120 degrees, and AX2E2 will be less than 109.5 degrees. Those are the expected bond angles if all of the regions of electron density were atoms. But the lone pair-bonding pair repulsion is stronger than the bonding pair-bonding pair repulsion, so the atoms will be pushed closer together than these values.

[Junxi Feng 3B]

Both VSEPR shape with the formula AX2E and AX2E2 have bent shape. What are the differences in their bond angles?

I think AX2E2 will have a lower bond angle, because the extra lone pair will create a large repulsion which will push the atoms closer to each other and thus a smaller bond angle.

[Arianna Perea 3H]

So whenever the central atom has a lone pair accompanied by a bond on each side, the shape will be bent?

[Aayush Patel 3B]

If a molecule has 3 total domains, then one lone pair and two bonded atoms will result in a bent shape.

[Louise Lin 2B]

If the central atom has two bonded pairs and either one or two lone pairs, this would result in the bent shape. The bond angle would be smaller if the central atom has two lone pairs because of electron repulsion.