2E.21 a & d

(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Ryan Chang 1C
Posts: 105
Joined: Sat Aug 24, 2019 12:17 am

2E.21 a & d

Postby Ryan Chang 1C » Fri Nov 15, 2019 5:19 pm

Could someone explain the shape and bond angles of C2H4? I don't understand why it's trigonal planar.

Also, I don't understand the answer for the shape and bond angles of N2H4. If someone could explain that as well that would be great!

Minh Ngo 4G
Posts: 137
Joined: Thu Jul 25, 2019 12:17 am

Re: 2E.21 a & d

Postby Minh Ngo 4G » Fri Nov 15, 2019 5:35 pm

C2H4 is trigonal planar around the C atom because it bonds to 2 H and double bond to another C, therefore it has 3 e- density around it => trigonal planar.

Minh Ngo 4G
Posts: 137
Joined: Thu Jul 25, 2019 12:17 am

Re: 2E.21 a & d

Postby Minh Ngo 4G » Fri Nov 15, 2019 5:37 pm

Ryan Chang 3A wrote:Could someone explain the shape and bond angles of C2H4? I don't understand why it's trigonal planar.

Also, I don't understand the answer for the shape and bond angles of N2H4. If someone could explain that as well that would be great!


As of shape and bond angles of N2H4, the lewis structure for it is N bonds to 2 H and 1 N, with 1 lone pair => shape: trigonal pyramidal => angles: <109.5


Return to “Determining Molecular Shape (VSEPR)”