C2H4

(Polar molecules, Non-polar molecules, etc.)

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ayushibanerjee06
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Joined: Thu Jul 11, 2019 12:16 am

C2H4

Postby ayushibanerjee06 » Fri Nov 15, 2019 5:29 pm

can someone explain c2h4's shape and bond angles? I don't understand why it is 120 degrees

Chem_Mod
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Re: C2H4

Postby Chem_Mod » Fri Nov 15, 2019 6:24 pm

Since C2H4 has a carbon with a double bond and two hydrogen molecules one each side, there are no lone pairs on carbon. Therefore, each carbon will have a trigonal planar shape meaning the H-C-H bond angle will be 120 degrees and the H-C-C will also be 120 degrees.

Alan Wu
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Joined: Sat Sep 14, 2019 12:16 am

Re: C2H4

Postby Alan Wu » Fri Nov 15, 2019 6:25 pm

In C2H4, consider each carbon as a central atom by itself. Each carbon atom has 3 electron density regions around it, so each carbon can have the VSEPR formula AX3. Therefore, there's essentially 2 trigonal planar molecules joined together in C2H4, so the bond angles are around 120 degrees.

Maeve Miller 1A
Posts: 51
Joined: Fri Aug 09, 2019 12:16 am

Re: C2H4

Postby Maeve Miller 1A » Fri Nov 15, 2019 7:54 pm

Though C2H4 is a chain, in doing VSEPR models, you have to treat each carbon as the central atom. Each carbon would have 3 areas of electron density (all bonds), making it trigonal planar, which has bond angles of 120 degrees. Hope this helps :)


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